Question
Compute the maximum total of (r + s) if ‘6r427s8’ is
divisible by 12.Solution
ATQ,
Check divisibility by 4 and 3.
Last two digits: ‘s8’ ⇒ s = 0, 2, 4, 6, 8
Maximum s = 8
Sum = 6 + r + 4 + 2 + 7 + 8 + 8 = 35 + r
35 + r divisible by 3 → r = 1, 4, 7
Max r = 7
Max (r + s) = 7 + 8 = 15
(129.98% of 8460) + (119.899% of 8640) = (130.009% of 15820) + ?
20.57 ×28.04 ÷ ? + 254 = 429.06
(21.02 × 5.83 × 12.03 ÷ 6.99 of 4.03) + 31.93% of 50.03 = ?
(74.93% of 640.11 + 3/4 of 359.79)² - (1/3 of 80.87 × 2)² = ?
177.05 = 25.06% of 3631.97 + 16.02% of 3750.08 – ?3
? = 16.08 + 13.99 × 25.07
P spends 30% of his income to groceries, another 30% to rent, and 40% of what is left to bus fare. If his sole expenses are groce...
8.15 of 124.95 ÷ 40.13 + 249.84 X 14.18 - √325 X 149.87 = ? X 10.85
(359.92÷24.02)+(230.04÷5)=?% of 210.0-86.1
20.06% of 359.89 - 15.95 X ? + 18.07 X 14.95 = 48.87 X 6.02
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