Question
What is the smallest number that must be added to 1500 so
that it becomes exactly divisible by 47?Solution
ATQ,
On dividing 1500 by 47 we get remainder 41
Now, 47 – 41 = 6
If we add 6 to 1500, then the resultant number will be completely divisible by 47.
So, required number = 6
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