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    Question

    What is the smallest number that must be added to 1500 so

    that it becomes exactly divisible by 47?
    B 6 Correct Answer Incorrect Answer
    C 3 Correct Answer Incorrect Answer
    D 4 Correct Answer Incorrect Answer

    Solution

    ATQ,

    On dividing 1500 by 47 we get remainder 41

    Now, 47 – 41 = 6

    If we add 6 to 1500, then the resultant number will be completely divisible by 47.

    So, required number = 6

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