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Let ones and tens digit of the number be 'a' and 'b' respectively.
So, original number = 10b + a
Reverse number = 10a + b
So, a + b = 7 --------- (I)
And, 10b + a - 45 = 10a + b
Or, 9b - 9a = 45
Or, b - a = 5 ---------- (II)
On adding equation I and II,
We get, a + b + b - a = 7 + 5
Or, 2b = 12
Or, 'b' = 6
On putting value of 'b' in equation I,
We get, 6 + a = 7
Or, 'a' = 1
Required number = 10 x 6 + 1 = 61
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