Question
Four friends A, B, C and D together have 240 pens. The
number of pens with A is 1/4th the total number of pens with other three. Pens with B are 1/3rd of the total pens with the other three. C has 3/7th of the pens with other people. Who has the maximum number of pens and what is the number?Solution
Let the number of pens with B, C and D be 4m then the number of pen with A will be m.Hence, m + 4m = 240=> 5m = 240=> m = 48In the similar way we can calculate the number of pens with B, C and D respectively.So number of pens with B, C and D will be 60, 72, and 60 respectively.Hence C has the maximum number of pens.
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