Question
110, 112, 116, 122, 130,
? Find the number in place of (?) in the given number seriesSolution
ATQ, 110 + 2 = 112 112 + 4 = 116 116 + 6 = 122 122 + 8 = 130 130 + 10 = 140
More Missing Series Questions
216% of 350 + 273 = ?2 × 21
13/3 – (23/6) = ? – (22/9)
(360 - ?)/(25% of 96) = 13
116*2/3% of 18600 + 666*2/3% of 1290 = 457*1/7% of 1750 + 555*5/9% of 3150 + ?
√? = 80% of 720 - 22% of 2500
Simplify: (1 ÷ 0.08)
25% of 60 × 15% of 120 = 30% of (?)
(30 × 0.80)⁴ ÷ (2160 ÷ 60)⁴ × (54 × 16)⁴ = (6 × 4)?+5
∛157464 =?
(512) (2/3) × √64 ÷ (512) (1/3) = (64) (?/2) ÷ (2)6
