Question
Find the number of zeros in
58!.Solution
Divide ‘58!’ by 5 and take the quotient in consideration. Since, (58/5) gives a quotient of ‘11’. Now, again divide ‘11’ by ‘’5’ and take the quotient in consideration and repeat this process until ‘0’ is obtained as quotient. Now, (11/5) will give ‘2’ as quotient So, required number of zeros = sum of quotients obtained = 11 + 2 = 13
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