Question
A shopkeeper has milk of 3 different qualities. The first quality is 621 liters, the second quality is 644 liters, and the third quality is 690 liters. Find the minimum possible number of bottles of equal size, which can be filled with different milk of different quality without mixing.
Solution
First quality milk =621 liters = 3×3×3×23 Second quality milk =644 liters= 2×2×7×23 Third quality milk =690 liters = 2×3×5×23 HCF =23 The minimum possible number of bottles of same size is- =621/23 +644/23 +690/23 =27+28+30=85.
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