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    Question

    Sum of squares of three consecutive numbers is 1325.

    Find the sum of first and third number.
    A 42 Correct Answer Incorrect Answer
    B 30 Correct Answer Incorrect Answer
    C 34 Correct Answer Incorrect Answer
    D 46 Correct Answer Incorrect Answer

    Solution

    Let the numbers be (x тАУ 1), x and (x + 1) => (x тАУ 1)2┬а+ x2┬а+ (x + 1)2┬а= 1325 => x2┬атАУ 2x + 1 + x2┬а+ x2┬а+ 2x + 1 = 1325 => 3x2┬а= 1325┬а- 2 => x2┬а= 1323/3 => x2┬а= 441 => x = 21 Required sum = (21 тАУ 1) + (21 + 1) = 42

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