A mixture of milk and water contains 64% water and 72 litres milk. '2p' litres of mixture is now removed and 18 litres milk is added. Find the quantity of water in resultant mixture if quantity of water is 33 (1/3)% more than that of milk in resultant mixture.

Total quantity of initial mixture = (72/0.36) = 200 litres Initial quantity of water = 0.64 X 200 = 128 litres Ratio of initial quantity of milk and water respectively = 72:128 = 9:16 Quantity of water removed = (16/25) X 2p = (32p/25) litres Quantity of milk removed = (9/25) X 2p = (18p/25) litres Quantity of water in resultant mixture = 128 - (32p/25) = [(3200 - 32p) /25] litres Quantity of milk in resultant mixture = 72 - (18p/25) + 18 = [(2250 - 18p) /25] litres So, [(3200 - 32p) /25]: [(2250 - 18p) /25] = 4:3 Or, 3 X (3,200 - 32p) = 4 X (2,250 - 18p) Or, 9,600 - 96p = 9,000 - 72p Or, 24p = 600 Or, 'p' = 25 Therefore, required quantity of water = (3,200 - 32 X 25) ÷ 25 = (2,400/25) = 96 litres