Question
A container has 40 litres of a mixture of milk and water in the ratio 3 : 1 . How many litres of water must be added so that the new ratio of milk to water becomes 3 : 2 ?
Solution
Milk = (3/4) × 40 = 30 L Water = 10 L Let x litres of water be added. New water = 10 + x Required ratio: 30 : (10 + x) = 3 : 2 30 / (10 + x) = 3 / 2 Cross-multiply: 60 = 3(10 + x) 60 = 30 + 3x 3x = 30 → x = 10 L
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