Question
A container has a mixture of juice and soda in the ratio
4:1. If half of the mixture is removed and replaced by 15 litres of soda, the resulting ratio of juice to soda becomes 8:7. What was the original quantity of the mixture?Solution
ATQ,
Let the initial quantity of the mixture = β2xβ litres Then, quantity of the mixture left after removing half = βxβ litres In βxβ litres of mixture, let quantity of juice = β4yβ litres In βxβ litres of mixture, let quantity of soda = β1yβ litres According to the question, 4y / (y + 15) = 8/7 β 7 Γ 4y = 8 Γ (y + 15) β 28y = 8y + 120 β 20y = 120 β y = 6 So, x = 4y + y = 5y = 5 Γ 6 = 30 litres Initial quantity of the mixture = 2x = 2 Γ 30 = 60 litres
Statements: Q > M > Y < N = H β₯ S < V < R β€ K
Conclusion
I: K > Y
II: N > S
Statements: I β₯ E = S > J < N > V > Q β€ O
Conclusion
I: I > S
II: Q < N
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