Question
A vessel holds ‘4x’ litres of milk and ‘3y’
litres of water. When 25 litres of water is poured into it, the milk to water ratio becomes 8:7. However, if 15 litres of water is added instead, the ratio of water to milk becomes 5:6. What is the original quantity of milk (in litres) in the vessel?Solution
ATQ,
According to the question, {4x/(3y + 25)} = 8/7 Or, 28x = 24y + 200 Or, 7x – 6y = 50…….. (1) Also, {4x/(3y + 15)} = 6/5 Or, 20x = 18y + 90 Or, 10x – 9y = 45…….. (2) Equation (1) × 3 – Equation (2) × 2, we get 21x – 18y – 20x + 18y = 150 – 90 Or, x = 60 So, initial quantity of milk in the mixture = 4x = 4 × 60 = 240 litres
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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