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Milk in the mixture = (3/5) × 60 = 36 liters. Water in the mixture = (2/5) × 60 = 24 liters. Let x liters of water be added. New quantity of water = 24 + x. New ratio = Milk : Water = 3:4. 36 / (24 + x) = 3 / 4. Cross-multiply: 4 × 36 = 3 × (24 + x) 144 = 72 + 3x 72 = 3x x = 24 liters.
((99.9 - 20.9)² + (99.9 + 20.9)² )/(99.9 x 99.9 + 20.9 x 20.9) = ?
...[a/(2a² + 5a + 2)] = 1/6 , then find the value of (a+1)/a ?
If (p/q) = (7/8) and (q/r) = (3/11), then the find the value of {(r – p)/(p + q)}.
(408 × 680)÷(20% of 680) = (250 × 260)÷ 10 + ? – 4500
If x:y:z = 3:4:6, and (5x + 3z) = 132, then find the value of '3y'.
If x2 - 3x + 2 is a factor of, x4 - px2 + q, then (p, q) =