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    Question

    A container contains a mixture of 50 liters of milk and

    water in the ratio 5:3. If 8 liters of the mixture is taken out and replaced by water, what is the new ratio of milk to water in the container?
    A 20: 17 Correct Answer Incorrect Answer
    B 21: 19 Correct Answer Incorrect Answer
    C 15: 11 Correct Answer Incorrect Answer
    D 14: 11 Correct Answer Incorrect Answer

    Solution

    Initial amount of milk = (5/8) × 50 = 31.25 liters, Initial amount of water = (3/8) × 50 = 18.75 liters. When 8 liters of the mixture is taken out, the amount of milk and water removed is in the ratio 5:3. Milk removed = (5/8) × 8 = 5 liters, Water removed = (3/8) × 8 = 3 liters. After removing, the amount of milk = 31.25 - 5 = 26.25 liters, Amount of water = 18.75 - 3 + 8 = 23.75 liters (since 8 liters of water is added back). Now, the new ratio of milk to water is: 26.25:23.75 = 21:19

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