Question
Bowl 'P' initially holds 'a' liters of pure petrol.
First, 25% of the petrol is removed and replaced with an equal amount of diesel. Subsequently, 40 liters of this mixture is removed, after which the remaining mixture contains 65 liters of diesel. Calculate the initial value of 'a'.Solution
ATQ, we can find the final quantity of the milk in the resultant mixture by using the formula Final quantity of milk = X{1 β (b/X)}t, where X = initial quantity of milk, b = quantity of milk/mixture replaced and t = number of times the process is repeated. Therefore, a{1 β (0.25a/a)}{1 β (40/a)} = a β 65 Or, 0.75(a β 40) = a β 65 Or, a β 0.75a = 65 β 30 Or, a = 35/0.25 = 140
12.5% of (100 + ?) = 40
2/9 of 5/8 of 3/25 of ? = 40
24 Γ β? + 4008 Γ· 24 = 40% of 200 + 327
7(1/2) – 3(5/6) = ? − 2(7/12)
280 Γ· 14 + 11 Γ 12 β 15 Γ 6 = ?Β
1550 Γ· 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)Β Β Β Β Β Β
25% of 1000 + 10% of 150 β 22 Γ ? = 45
β 729 Γ 5 β 220 % of 15 + ? = 120% of 160
What will come in the place of question mark (?) in the given expression?
(40% of ? Γ 43 ) β 232 = 751Β
180 % of 45 + β144 Γ 8 = ?2 Β + 80 % of 70