Question
A solution contains petrol and kerosene in a ratio of
3:5. 16 liters of the solution is replaced with petrol to make a ratio of 5:3. Find the original amount of kerosene in the solution.Solution
X=40. Original amount of kerosene= (5/8) ×40=25 liter
The minimum value of 25 sin2 θ + 16 cos2 θ is
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