Question
36 liters of milk were kept in a container. 1.8 liters
were removed and replaced with water. This procedure was performed one more time. How much milk does the container now hold?Solution
we know. remaining milk in the container = Original amount × [1- amount taken out /original amount] ⁿ = 36[1-1.8/36] ² =36[1-1/20] ² = 36[19/20] ² =36×361/400 =361×9/100 =3249/100=32.49
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