Question
Mixture ‘A’ contains 80% acetone and rest 30
litres water. Mixture ‘B’ contains 72 litres acetone and rest 50% water. When two mixtures are mixed, then find the ratio of acetone to water in the resultant mixture.Solution
Quantity of water in mixture ‘A’ = 30 litres Total quantity of mixture ‘A’ = 30/0.2 = 150 litres Therefore, quantity of acetone in mixture ‘A’ = 150 – 30 = 120 litres Quantity of acetone in mixture ‘B’ = 72 litres Total quantity of mixture ‘B’ = 72/0.50 = 144 litres Quantity of water in mixture ‘B’ = 144 – 72 = 72 litres Therefore, quantity of acetone in resultant mixture = 144 + 72 = 192 litres Quantity of water in resultant mixture = 30 + 72 = 102 litres Required ratio = 192:102 = 32:17
18, 34, 70, 134, ?, 378
216, 81, 297, 378, ?, 1035, 1728
Find the missing number in the given number series.
3, 7, 18, 38, 69, ?Find the missing number in the given number series.
4, ?, 110, 665, 4660, 37285
244, 179, 129, 92, 66, ?
16, 20, 47, 63, 188, ?
18 19 34 111 428 2165 ?
...76, 80, 89, 105, ?, 166
48, 24.5, ?, 39.75, 81.5, 206.25, 621.75
6 11 32 111 ? 2345 14100
...