Question
Mixture ‘A’ contains 80% acetone and rest 30
litres water. Mixture ‘B’ contains 72 litres acetone and rest 50% water. When two mixtures are mixed, then find the ratio of acetone to water in the resultant mixture.Solution
Quantity of water in mixture ‘A’ = 30 litres Total quantity of mixture ‘A’ = 30/0.2 = 150 litres Therefore, quantity of acetone in mixture ‘A’ = 150 – 30 = 120 litres Quantity of acetone in mixture ‘B’ = 72 litres Total quantity of mixture ‘B’ = 72/0.50 = 144 litres Quantity of water in mixture ‘B’ = 144 – 72 = 72 litres Therefore, quantity of acetone in resultant mixture = 144 + 72 = 192 litres Quantity of water in resultant mixture = 30 + 72 = 102 litres Required ratio = 192:102 = 32:17
5/13 Γ 104 + 1(2/9) Γ 198 = 133 + ?
What will come in the place of question mark (?) in the given expression?
(24 2 β 16 2 ) + 75% of 40% of 480 = ?
5 + 2 Γ 3 Γ· (3 Γ 2) Γ· 4
Find the Value of β(-β3+β(3+8β(7+4β3)))?Β
- What will come in the place of question mark (?) in the given expression?
35% of 400 - 20% of 300 = (? - 30) X 2 15848 Γ· 4 β 793 Γ 6 + 3628 = 3 Γ ?
? = (22% of 25% of 60% of 3000) + 21
What will come in place of the question mark (?) in the following expression?
(320 Γ· 8 + 22) Γ 4 = 60 + 40% of ?
70 % of 640 + 75 % of 360 - 19 Γ 12 = ?
24 × ?2 – 11 × 4 = 1900