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    Question

    Mixture β€˜A’ contains 80% acetone and rest 32 litres

    water. Mixture β€˜B’ contains 70 litres acetone and rest 50% water. When two mixtures are mixed, then find the ratio of acetone to water in the resultant mixture.
    A 31:17 Correct Answer Incorrect Answer
    B 33:19 Correct Answer Incorrect Answer
    C 33:17 Correct Answer Incorrect Answer
    D 32:17 Correct Answer Incorrect Answer

    Solution

    Quantity of water in mixture β€˜A’ = 32 litres Total quantity of mixture β€˜A’ = 32/0.20 = 160 litres Therefore, quantity of acetone in mixture β€˜A’ = 160 – 32 = 128 litres Quantity of acetone in mixture β€˜B’ = 70 litres Total quantity of mixture β€˜B’ = 70/0.50 = 140 litres Quantity of water in mixture β€˜B’ = 140 – 70 = 70 litres Therefore, quantity of acetone in resultant mixture = 128 + 70 = 198 litres Quantity of water in resultant mixture = 70 + 32 = 102 litres Required ratio = 198 : 102 = 33:17

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