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    Question

    A cylindrical tank of 28 cm base radius is partly filled

    with water. How many spherical iron balls of 1cm radius are added in it in order to increase the water level by 5cm?
    A 2940 Correct Answer Incorrect Answer
    B 3250 Correct Answer Incorrect Answer
    C 4245 Correct Answer Incorrect Answer
    D 6433 Correct Answer Incorrect Answer

    Solution

    Base radius of a cylindrical tank = 28 cm Change in the rise of water in a cylindrical tank = Volume of a bullet Radius of a iron = 1 cm No. of bullets = (Change in the rise of water in a cylindrical tank )/(Volume of a bullet ) = (π r2h)/((4 )/(3 ) π r3) = (π × 28 × 28 × 5 )/(π (4 )/(3 ) × 13) = (28 × 28 × 5 × 3 )/(4 ) = 2,940 To increase the water level by 5cm we need 2,940 bullets.

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