Question
Find the perimeter of a rectangle whose length is 30 cm
more than the side of a square whose perimeter is 64 cm. The breadth of rectangle is 18 cm less than its length.Solution
ATQ, Side of square = (64 ÷ 4) = 16 cm Length of rectangle = 16 + 30 = 46 cm Breadth of rectangle = 46 − 18 = 28 cm Therefore, perimeter of rectangle = 2 × (46 + 28) = 148 cm
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