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ATQ,
TSA = 2 × π × r × (r + h)
So, 2 × (22/7) × 25 × (25 + height) = 6,600
Or, 25 + height = 21
Or, height = -4 cm
Now, k + 10 = -4
Or, k = -14
Required value = (-14)² = 196
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