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Let the radius and height of the cone be 'r' cm and 'h' cm respectively. We have, (r + h) = 31 And h = r + 17 So, r + h = r + r + 17 = 31 Or, r = (31 - 17) ÷ 2 = 7 cm So, h = 7 + 17 = 24 cm Also, slant height of the cone = √(r2 + h2) = √(7 2 + 24 2) = 25 cm Therefore, curved surface area of the cone = π X radius X slant height = (22/7) X 7 X 25 = 550 cm2
If ‘REALISE’ is coded as ‘9’, ‘PAMPHLET’ is coded as ‘8’, then what is the code for ‘PROPOSE’ in the same code language?
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s _ u v _ x _...
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