Question
The ratio of the sum of the
parallel sides of a trapezium to its height is 4:5, and its area is 360 m². If the length of a rectangle is equal to the height of the trapezium, and the breadth of the rectangle is 15 m greater than the height of the trapezium, what is the area of the rectangle?Solution
ATQ, let the sum of the parallel sides of a trapezium to its height can be '4a' and '5a' respectively. 1/2 × 4a × 5a = 360 a = 36 a = 6 Height of the trapezium = 5×6 = 30m Length of the rectangle = 30m Breadth of the rectangle = 15+30 = 45m Area of the rectangle = 30×45 = 1350m2
An LPP has constraints:
x + y ≤ 4
x + y ≥ 6
x, y ≥ 0
What can be said about the feasible region?
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