Question
The ratio of the sum of the
parallel sides of a trapezium to its height is 4:5, and its area is 360 m². If the length of a rectangle is equal to the height of the trapezium, and the breadth of the rectangle is 15 m greater than the height of the trapezium, what is the area of the rectangle?Solution
ATQ, let the sum of the parallel sides of a trapezium to its height can be '4a' and '5a' respectively. 1/2 × 4a × 5a = 360 a = 36 a = 6 Height of the trapezium = 5×6 = 30m Length of the rectangle = 30m Breadth of the rectangle = 15+30 = 45m Area of the rectangle = 30×45 = 1350m2
The value of ((0.27)2-(0.13)2) / (0.27 + 0.13) is:
4.56 + 56.4 + 64.5 = ? + 10.46
(3/7) x 868 + 25% of 240 = (? + 65)
(506 ÷ 22 + 9 × 3) × ? = 900 ÷ 9
(72 + 30) ÷ 6 + [{75 ÷ 25) + 6} × 2] = ?
(560 ÷ 32) × (720 ÷ 48) = ?
√729 × 5 + 270 - 3 ÷ ∛27 + 4 × ? = 484
(392 + 427 + 226 – 325) ÷ (441 + 128 – 425) = ?Â
212.3 × 4414.7 × 4623.4 × 4845.85 = 462?
‘A’ and ‘B’ invested Rs. 5000 and Rs. 4200, respectively in a business, together. After 7 months, ‘A’ withdrew 25% of his initial investment...