Question
The length and width of a rectangle are in the ratio of
11:8. Additionally, the length of the rectangle is 54 cm less than its perimeter. Using this information, determine the area of the rectangle.Solution
Let the length and breadth of the rectangle be '11x' cm and '8x' cm, respectively. ATQ; 2 X (11x + 8x) = 54 + 11x Or, 38x = 54 + 11x Or, 27x = 54 So, x = 2 So, area of the rectangle = 11x X 8x = 88 X 4 = 352 cm2
More Mensuration Questions
236.23 - 653.23 + 696.23 = ?
Simplify:
Simplify the following expression:
(506 ÷ 22 + 9 × 3) × ? = 900 ÷ 9
What will come in place of (?) in the given expression.
√625 + 12 × 5 = ?[(15)³ × (8)²] ÷ (90 × 6) = ?²
(√529 + 63 /8)% of 800 = ?% of 250
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
Simplify the following expression:-
25% of {(5/18) × 2880 + 122 } = ?% of 590
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