Question
Volume of material used in constructing a hollow
cylinder of height 24 cm and thickness 1 cm is 96Ï€. What is the sum of the internal and external radii?Solution
Let external and internal radius of the cylinder be R and r cm respectively. Thickness of cylinder (R - r) = 1 cm. Height of the radius h = 24 cm As we know, Volume of hollow cylinder = π (R2 – r²) h π (R2 – r²) h = 96π  π (R + r) (R - r) h = 96π  (R+ r) x 1 x 24 = 96  (R+ r) = 96/24  (R + r) = 4 cm
If 0 ≤ θ ≤ 90°, and sec107 θ + cos107 θ = 2, then. (secθ + cosθ) is equal to:
If -5 ≤ x ≤ 3 and -1 ≤ y ≤ 0, then the minimum value of 2y – 3x is:
If sec θ + tan θ = m(> 1), then the value of sin θ is (0° < θ < 90°)
If x4 + 2x3 + ax2 + bx + 9 is a perfect square, where a and b are positive real numbers, then the value of a and b are
If α and β are the roots of equation x2 – x + 1 = 0, then which equation will have roots α3 and β3?
...If 8x2 + y2 − 12x − 4xy + 9 = 0, then the value of (14x − 5y) is :
If a + 1/a = -2 then the value of a1000 + a- 1000 is
Quantity I – 3
Quantity II – 254
If > 0 and < 0
Solve the cubic equation, x³ − 7x² + 14x − 8 = 0 and Find all real roots.
The value of x which satisfies the equation (x+a2+2c2) / (b+c) + (x+b2 +2a2) / (c+a) + (x+c+2b2) ...
Relevant for Exams:
