Question
AB is the diameter of a circle with center o. P is the
point on it If the cone ∠AOP is equal to 98 degrees then ∠OBP will be.Solution
∠ AOP = 98° ∠ POB = (180° - 98° ) = 82° Δ POB = ∠ P = ∠ B (Isosceles triangle) ∠ POB = 82° Δ ΡΟΒ = ∠ POB + ∠ OBP + 2 BPO = 180° 180° = 82°+ 2 x ∠ OBP 98/2 = ∠ OBP 49° =∠ OBP ∠ OBP =49° 
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