Question
AB is the diameter of a circle with center o. P is the
point on it If the cone ∠AOP is equal to 98 degrees then ∠OBP will be.Solution
∠AOP = 98° ∠POB = (180° - 98° ) = 82° Δ POB = ∠P = ∠B (Isosceles triangle) ∠POB = 82° Δ ΡΟΒ = ∠POB + ∠OBP + 2 BPO = 180° 180° = 82°+ 2 x ∠OBP 98/2 = ∠OBP 49° =∠OBP ∠OBP =49° 
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