Question
The area of the rectangular field is 800 m² and its
perimeter is 104 m. Find how much percent less the breadth of the field is compared to the length of the field?Solution
ATQ,
Given: Area = 800 m² Perimeter = 104 m Let length = L, breadth = B 2(L + B) = 104 → L + B = 52 → L = 52 − B L × B = 800 → (52 − B) × B = 800 → 52B − B² = 800 → B² − 52B + 800 = 0 Discriminant = 52² − 4×800 = 2704 − 3200 = −496 Hence, Can’t be determined — no real solution exists. Given area and perimeter are inconsistent.
35Â Â Â Â Â Â Â Â Â Â 36Â Â Â Â Â Â Â Â Â Â 40Â Â Â Â Â Â Â Â Â Â 49Â Â Â Â Â Â Â Â Â Â 65Â Â Â Â Â Â Â Â Â Â ?
...If   20       x      46      147       604        3045
Then, x% of 25 = ?
...10 625 50 125 250 25 ?
...2, 12, 36, 80, ?, 252
69    119    156    ?     199    209
15 , 33 , 71 , 150 , 307 , 625
52 25 27 ? 208 1648
...1400      350       700       175        ?       87.5
...7Â Â Â Â Â 14Â Â Â Â Â 42Â Â Â Â Â 168Â Â Â Â Â Â 840Â Â Â Â Â ?
...729 512 343 216 125 ?
...
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