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    Question

    The area of the rectangular field is 800 m² and its

    perimeter is 104 m. Find how much percent less the breadth of the field is compared to the length of the field?
    A 55% Correct Answer Incorrect Answer
    B 65% Correct Answer Incorrect Answer
    C 70% Correct Answer Incorrect Answer
    D 45% Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ, Let the length and the breadth of the rectangular field be ‘l’ meter and ‘b’ meter, respectively. So, the area of the rectangular field = l × b = 800 l = 800/b Perimeter of the rectangular field = 2(l + b) = 104 l + b = 52 800/b + b = 52 800 + b² = 52b b² – 52b + 800 = 0 b² – 40b – 12b + 800 = 0 b(b – 40) – 12(b – 40) = 0 (b – 12)(b – 40) = 0 b = 40, 12 b = 12 m and l = 40 m as length is greater than breadth So, the desired percentage = {(40 – 12)/40} × 100 = 70%

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