Question
Radius of a cylindrical vessel is 3cm less than breadth
of rectangle, while height of cylindrical vessel is equal to length of rectangle, whose area is 540 cm². If ratio between length & breadth of rectangle is 5:3, then find the thickness of 1 disc, if these discs are kept one above another in cylindrical vessel and 10 discs get completely fit in cylindrical vessel. (Let radius of discs equal to radius of cylindrical vessel)? type-sscSolution
. Let length & breadth of rectangle be 5x & 3x respectively  Given area of rectangle = 540 cm2  5x × 3x = 540 cm2  15x2 = 540  x2 = 36  x = 6 cm Radius of cylindrical vessel = 3 × 6 − 3 = 15 cm  Height of cylindrical vessel = 5 × 6 = 30 cm   Volume of cylindrical vessel = π × 15 ×15 × 30 = 6750 π cm3  Let thickness of each disc be x cm  So, 10 × π × x × 15 × 15 = 6750 π cm3  x = 6750/ (225 x 10) x = 5.88cm.
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