Question
A hemispherical bowl made of iron has an inner diameter
of 84 cm. Find the cost of tin plating it on the inside at the rate of Rs.21 per 100cm² take π=22/7Solution
Diameter = 84cm then r =42cm The total surface area of the hemispherical bowl = 4πr²/ 2 =πr² =2× (22/7) ×42×42 =2×22×42×6 =11088cm² Cost of tin plating = 100cm² = 21Rs 1cm² = .21 Rs then 11088cm² = .21 × 11088cm² =2328.48 Rs
2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 19Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 70...
6000 3002 1503 ? 378.75 191.375 97.6875
...If  204    196       223   x  284
Then, what is the average of the numbers of the above series?
...8   24    12    ?   18     54
3 ? 7 16 71 346
...104   106   110   113   ?   126
12, 18, 28, 42, 52, ?
18Â Â Â Â Â Â Â Â Â Â Â Â 29 Â Â Â Â Â Â Â Â Â Â Â Â Â Â 51 Â Â Â Â Â Â Â Â 84 Â Â Â Â Â Â Â Â 128 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 182
5, 8, 17, ?, 37, 48
(32.03 + 111.98) ÷ 18.211 = 89.9 – 20.23% of ?
Relevant for Exams:
