A circular wire enclosing the area of 9,856 cm² is bent to form a square. How much area will be enclosed by that wire?

A =`pir^2` ⇒ 9,856 =`22/7xxr^2` r^{2} = 9,856 `xx7/22` = 3136 r =`sqrt3136` = 56 cm Circumference = 2`pi` r = 2`xx22/7xx56` = 352 cm Hence, perimeter of required square = 4a = 352 cm a = 88 cm Hence, required area = a² = 88 `xx` 88 = 7,744 cm²

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