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    Question

    A circular wire enclosing the area of 9,856 cm² is

    bent to form a square. How much area will be enclosed by that wire?
    A 6,334 cm┬▓ Correct Answer Incorrect Answer
    B 7,744 cm┬▓ Correct Answer Incorrect Answer
    C 4,654 cm┬▓ Correct Answer Incorrect Answer
    D 5,540cm┬▓ Correct Answer Incorrect Answer

    Solution

    A = `pir^2` ⇒ 9,856 =`22/7xxr^2` r2 = 9,856 `xx7/22` = 3136 r =`sqrt3136` = 56 cm Circumference = 2`pi` r = 2`xx22/7xx56` = 352 cm Hence, perimeter of required square = 4a = 352 cm a = 88 cm Hence, required area = a² = 88 `xx` 88 = 7,744 cm²

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