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Let the length of each side of the square land = ‘x’ metres Then, perimeter of the land = 4x = 116 metres So, x = (116/4) = 29 So, area of the square land = x2 = 292 = 841 m2 Area of the circular land = π × radius2 = (22/7) × 14 × 14 = 616 m2 Therefore, area to be levelled = 841 – 616 = 225 m2 Cost of leveling = 225 × 20 = Rs. 4500
Boolean algebra can be used ____________
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