Question
The volume of a cube is 3375 cm3. If the cost
of painting is Rs. 2.5/cm2 , then find the cost of painting the four faces of the cube.Solution
Let the length of edge of the cube be ‘a’ cm. ATQ; a3 = 3375 Or, a = 15 Area of four faces of the cube = 4 × 152 = 900 cm2 Required cost of painting = 900 × 2.5 = Rs. 2250
(22% of 1500 + 15% of 2200) = ? x 11
√14400 x √8100 - (60)² = ? + (80)²
4368 + 2158 – 596 - ? = 3421 + 1262
[4(1/3) + 4(1/4)] × 24 – 62 = ?2
What value should come in place of the question mark (?) in the following question?
1250 − ( 320 + 180 ) × ...
36×?² + (25% of 208 +13) = 60% of 2400 + 17×18
2850 ÷ 2.5 - ? × 42 = 300
(64/25)? × (125/512)?-1 = 5/8
- What will come in place of the question mark (?) in the following questions?
18×4+96÷8=? 3/7 of 504 ÷ 12 + 17 = √?