Question
If the two adjacent sides of a rectangle are x cm and x
– 10 cm and its perimeter is 108 cm then find its area?Solution
Let the length and breadth of rectangle = x and x – 10 cm Perimeter of rectangle = 2 x [Length + Breadth] According to the question Perimeter of rectangle = 108 cm ⇒ 2 x [Length + Breadth] = 108 ⇒ x + x – 10 = 54 ⇒ Length = x = 32 cm Breadth = (x – 10) = 22 cm Area of rectangle = Length x Breadth Area of rectangle = 32 x 22 Area of rectangle = 704 cm²
If the length of a rectangle is increased by 40%, and the breadth is decreased by 20%,then the area of the rectangle increases by x%. Then the value of ...
A number is increased by 20%, and the resulting number is decreased by 20%. If the initial number is ₹x, the final number is ₹2880. What is the valu...
Solve for x in the equation: 3(x + 2) + 2(2x - 5) = 5x + 9
(u - 5) 2 + (v + 2) 2 + (w – 4) 2 = 0, then find the value of 4u - v + w.
If x = (√13 + √12)/ (√13 - √12) and y = (√13 - √12)/(√13 + √12), then find the value of 4x2 – xy + 4y2.
...If a, b and c are integers such that a 2 + b 2 + c 2 = 228, a + b + c = 26 and b = c, then find the value of a?
Find ‘x’ if (x³+3x)/(3x²+1) = 189/61
What is the highest common factor of (x³ - x² - x - 15) and (x³ - 3x² - 3x + 9)?
If ( p = 40 - q - r ) and ( pq + r(q + p) = 720 ), then find the value of ( p2 + q2 + r2).
