Question
A circular wire of diameter 70 cm is folded in the shape
of a rectangle whose sides are in the ratio 3:2. Find the area enclosed by the rectangle.Solution
Using the formula, Area = lb & D = 2r and A = πr² Radius of circular wire = 70/2 = 35 cm Circumference of wire = 2πr = 2 x (22/7) x 35 = 220 cm Let the length and breadth of rectangle be 3x & 2x cm respectively. Therefore, perimeter of rectangle = 2(3x + 2x) = 10x According to the question, 10x = 220 ⇒ x = 220/10 = 22 Therefore, length of rectangle = 3x = 3 x 22 = 66 cm Breadth of rectangle = 2x = 2 x 22 = 44 cm Area = 66 x 44 = 2904 cm²
{(23.65 × 35.12) ÷ 6.97} + 179.86 = ? × 14.76
Find the approximate value of Question mark(?). No need to find the exact value.
(34.95 × 7.03) ÷ 5 + 27.98% of 249.88 – √(80.81) = ?
...What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
9.89 x 4.99 + 2.01 x 49.89 = ?% of 299.69
What approximate value will replace the question mark (?) in the following?
29.99...
What will be the approximate value of the following questions.
(74.75% of 600.29 – 44.85% of 399.99) × (√224.95 ÷ 15.01) = ?
( 1000)1/3  × 10.11 × 4.97 ÷ 10.32 =? – 15.022
12.03 x 4.21 +19.95% of 300.05 =Â ?
79.79% of 299.87 - 54.67% of (39.982 - 9.822 ) = ? - 19.92 × 199.98
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