Question
A well with 20 m inside diameter is dug 10 m deep. Soil
taken out of it has been evenly spread all around it to a width of 30 m to form an embankment. Find the height of the embankment.Solution
Volume of the soil dug out = πr2h ⟹ (22)/(7) x 10 x 10 x 10 = 3,142.85m³. Area of embankment = Area of embankment with well - Area of well =( (22)/(7) x 40 x 40) - ( (22)/(7) x 10 x 10 ) = 4,714 m² Height of embankment =(volume)/(area) = (3142.85)/(4714.3) = (2)/(3) m
Equation 1: x² - 200x + 9600 = 0
Equation 2: y² - 190y + 9025 = 0
I: x2Â + 31x + 228 = 0
II: y2 + 3y – 108 = 0
I). 5p2 Â - p - 4 = 0
II). q2 - 12q + 27 = 0
I). p2 - 26p + 165 = 0
II). q2 + 8q - 153 = 0
l). 3p + 2q = 27
ll). 4p - 3q = 2
I. 2b2 + 31b + 99 = 0
II. 4a2 + 8a - 45 = 0
I. 6x² + 77x + 121 = 0
II. y² + 9y - 22 = 0
I. 2p2 - 3p – 2 = 0 II. 2q2 - 11q + 15 = 0
I: √(100 x4 + 125x4) + 7x + 41/2 = -4x
II: 3√(64y3) x 2y + 19y + 72 = -3y +...
If the roots of the quadratic equation 6m² + 7m + 8 = 0 are α and β, then what is the value of [(1/α) + (1/β)]?
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