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    Question

    The angle of elevation of the top of a building from the

    foot of a tower is 30┬░ and the angle of elevation of the top of the tower from the foot of the building is 60┬░. If the height of the tower is 42 m, what is the height of the building?┬а
    A 42/тИЪ3 m Correct Answer Incorrect Answer
    B 14 m Correct Answer Incorrect Answer
    C 14тИЪ3 m Correct Answer Incorrect Answer
    D 42тИЪ3 m Correct Answer Incorrect Answer

    Solution

    Let AB and CD denote the tower and the building respectively. In тЦ│ABC, tan 60┬░ = AB/BC тЗТ тИЪ3 = 42/BC тЗТ BC = 42/тИЪ3 m In тЦ│BCD, tan 30┬░ = CD/BC тЗТ 1/тИЪ3 = CD/(42/тИЪ3) тЗТ CD = 14 m тЗТ h = 14 m

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