Question
The angle of elevation of the top of a building from the
foot of a tower is 30° and the angle of elevation of the top of the tower from the foot of the building is 60°. If the height of the tower is 18 m, what is the height of the building?Solution
Let AB and CD denote the tower and the building respectively. In △ABC, tan 60° = AB/BC ⇒ √3 = 18/BC ⇒ BC = 18/√3 m In △BCD, tan 30° = CD/BC ⇒ 1/√3 = CD/(18/√3) ⇒ CD = 6 m ⇒ h = 6 m
More Height and Distance Questions
- Suppose both the roots of q² + kq + 49 = 0 are real and equal, then determine the value of 'k'.
I. 84x² - 167x - 55 = 0
II. 247y² + 210y + 27 = 0
l). 2p² + 12p + 18 = 0
ll). 3q² + 13q + 12 = 0
I. 2x² - 9x + 10 = 0
II. 3y² + 11y + 6 = 0
I. 6x2 - 47x + 77 =0
II. 6y2 - 35y + 49 = 0
I. 12a2 – 55a + 63 = 0
II. 8b2 - 50 b + 77 = 0
...I. 2y2 – 19y + 35 = 0
II. 4x2 – 16x + 15 = 0
I. 5x² - 24 x + 28 = 0
II. 4y² - 8 y - 12= 0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x2 – ...
I.8(x+3)+ 8(-x)=72
II. 5(y+5)+ 5(-x)=150
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