The angle of elevation of the top of a building from the foot of a tower is 30° and the angle of elevation of the top of the tower from the foot of the building is 60°. If the height of the tower is 18 m, what is the height of the building?
Let AB and CD denote the tower and the building respectively. In △ABC, tan 60° = AB/BC ⇒ √3 = 18/BC ⇒ BC = 18/√3 m In △BCD, tan 30° = CD/BC ⇒ 1/√3 = CD/(18/√3) ⇒ CD = 6 m ⇒ h = 6 m
. COLUMN A COLUMN B
A)Transgressions must be sanctioned D)to Rwanda was a defining moment.
B)The 1996 Joint Evaluation of Emergency Assi...
