Let θ be the angle of depression of the point on the ground as seen from the top of a tower, here θ = 45° Let AC be the height of the tower, here AC = 50 feet. Let the distance of the point on the ground from the foot of the tower, AB = x feet. Here, tan θ = AC/AB ⇒ tan 45° = 50/x ⇒ 1 = 50/x ⇒ x = 50 feet
3/8 of 720 ÷ 15 + 12 = √?
(8.6 × 8.6 + 4.8 × 4.8 + 17.2 × 4.8) ÷ (8.62 – 4.82 ) = ? ÷ 19
Solve the following equation.
143 + 14.3 + 1.43 + 0.143 + 0.0143 =?
12 × 19 + 13 × 15 + 152 = ?% of 500
√3600% of 150 + 3/5 of 360 - ? = 210
[192 ÷ 6 × 5] ÷ (? + 3) = 20
2852 + 7848 + 2962 + 4268 = ? – 1460
345 × 20 ÷ 4 + 28 + 60 = ?
120% of 400 + ?% of 520 = 1000
(?) x 3 + 68 = √9025