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      Question

      A sniper on the parapet of a 50 feet high building was

      aiming at a target. The angle of depression that his rifle made was 45 ┬░. How far away from the building was his target?
      A 50/тИЪ3 feet Correct Answer Incorrect Answer
      B 25тИЪ3 feet Correct Answer Incorrect Answer
      C 50 feet Correct Answer Incorrect Answer
      D 50тИЪ3 feet Correct Answer Incorrect Answer

      Solution

      Let ╬╕ be the angle of depression of the point on the ground as seen from the top of a tower, here ╬╕ = 45┬░ Let AC be the height of the tower, here AC = 50 feet. Let the distance of the point on the ground from the foot of the tower, AB = x feet. Here, tan ╬╕ = AC/AB тЗТ tan 45┬░ = 50/x тЗТ 1 = 50/x тЗТ x = 50 feet

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