HCF of two numbers = 37 Hence, numbers are multiples of 37. Let the numbers be 37a and 37b, where ‘a’ and ‘b’ are prime numbers to each other. According to the question ∴ 37a + 37b = 444 (a + b) = 12 ∴ Required possible pairs of values of ‘a’ and ‘b’ are prime to each other are (1, 11) and (5, 7).
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