Question
Ratio of two numbers 3:7 and their LCM is 840. Find the
sum of the given two numbers.Solution
Let the two numbers be '3h' and '7h', where 'h' is the HCF of the two given numbers. Product of two numbers = (Product of LCM and HCF) of the given two numbers 3h × 7h = h × 840 Or, 21h = 840 So, 'h' = (840 / 21) = 40 Therefore, the required sum = 3h + 7h = 10h = 10 × 40 = 400 Hence, option c
What will be the product of smaller roots of both equations.Â
I. 2x² - 12x + 16 = 0  Â
II. 4y² - 8y - 12 = 0  Â
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 54x + 704 = 0
Equation 2: y² - 44y + 448 = 0
I. 5x² = 19x – 12
II. 5y² + 11y = 12
I. 3x² - 22 x + 40 = 0 Â
II. 4y² + 22y + 24 = 0  Â
I. x2 – 9x + 18 = 0
II. y2 – 5y + 6 = 0
I. p2 + 2p – 8 = 0 II. q2 – 5q + 6 = 0
I. 5x² - 28x + 39 = 0
II. 2y² - 13y + 20 = 0
I. 3x2Â + 3x - 60 = 0Â Â Â Â Â
II. 2y2Â - 7y + 5 = 0Â
I. 2y2Â + 11y + 15 = 0
II. 3x2Â + 4x - 4= 0
Relevant for Exams:
