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    • Question

      The total and the difference of L.C.M and H.C.F of two

      numbers is 378 and 126. If one of the numbers is 27, what is the other number?
      A 1176 Correct Answer Incorrect Answer
      B 1744 Correct Answer Incorrect Answer
      C 1639 Correct Answer Incorrect Answer
      D 1826 Correct Answer Incorrect Answer

      Solution

      ATQ,

      Let the L.C.M and the H.C.F of the two numbers be 'a' and 'b' respectively

      Then, (a + b) = 378

      And (a - b) = 126

      So, (a + b) + (a - b) = 378 + 126 = 504

      Or, a = 504 ÷ 2 = 252

      So, b = 378 - 252 = 126

      The product of two numbers is equal to the product of their L.C.M and H.C.FSo, required number = (252 × 126) ÷ 27 = 1176

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