Question
The least number which when divided by 8, 12, 16 and 18 leave zero remainder in each case and when divided by 22 leaves a remainder of 12 is:
Solution
LCM of 8, 12, 16 and 18 = 144 Required number = 144, because it is exactly divisible by 8, 12, 16 and 18Â and it leaves remainder 12 when divided by 22.
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