Question
The least number which when divided by 4, 6, 10 and 12
leave zero remainder in each case and when divided by 13 leaves a remainder of 8 is:Solution
LCM of 4, 6, 10 and 12Â = 60 Required number = 60, because it is exactly divisible by 4, 6, 10 and 12Â and it leaves remainder 8 when divided by 13.
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