Question
The least number which when divided by 8, 10, 12 and 15
leave zero remainder in each case and when divided by 16 leaves a remainder of 8 is:Solution
LCM of 8, 10, 12 and 15Â = 120 Required number = 120, because it is exactly divisible by 8, 10, 12 and 15Â and it leaves remainder 8 when divided by 16.
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