Question
Let N be the greatest number that will divide 89, 110,
131 leaving the same remainder in each case. Then sum of the digits in N is:Solution
To find the greatest number that leaves common remainder in each case, The HCF of (110-89), (131-89), (131-110) = 21 In this case the number will be 21. And sum of digits will be = 3
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Obscure
Repentance
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PERILOUS
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