Question
Let N be the greatest number that will divide 89, 110,
131 leaving the same remainder in each case. Then sum of the digits in N is:Solution
To find the greatest number that leaves common remainder in each case, The HCF of (110-89), (131-89), (131-110) = 21 In this case the number will be 21. And sum of digits will be = 3
Select the wrong term in the series.
312, 320, 304, 328, 295, 336
Identify the letter-cluster that does not belong to the following series.
RBK, TYM, VVO, XSP, ZPS, BMU
Select the number from among the given options that is wrong in the following series.
22, 30, 46, 78, 146, 270
Find the wrong number in the given series.
9, 18, 54, 270, 1899, 20790
Select the wrong number from the given alternatives.
64, 32, 32, 48, 98, 240
Find the wrong number in the given series.
17, 17, 51, 255, 1789, 16065
Find the wrong number in the given series.
75, 85, 76, 84, 77, 83, 78, 81, 79
Find the wrong number in the following number series:
2500, 1000, 400, 160, 60
In this question, one term in the number series is wrong. Find out the wrong term.
110, 115, 123, 134, 148, 163, 185
A series is given with one wrong term. Select the wrong number from the given series.
17, 29, 43, 59, 77, 97, 112
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