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    Question

    Let N be the greatest number that will divide 89, 110,

    131 leaving the same remainder in each case. Then sum of the digits in N is:
    A 3 Correct Answer Incorrect Answer
    B 7 Correct Answer Incorrect Answer
    C 4 Correct Answer Incorrect Answer
    D 6 Correct Answer Incorrect Answer

    Solution

    To find the greatest number that leaves common remainder in each case, The HCF of (110-89), (131-89), (131-110) = 21 In this case the number will be 21. And sum of digits will be = 3

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