Question

    Let N be the greatest number that will divide 82, 105,

    128 leaving the same remainder in each case. Then sum of the digits in N is:
    A 5 Correct Answer Incorrect Answer
    B 7 Correct Answer Incorrect Answer
    C 6 Correct Answer Incorrect Answer
    D 4 Correct Answer Incorrect Answer

    Solution

    To find the greatest number that leaves common remainder in each case, The HCF of (105-82), (128-82), (128-105) = 23 In this case the number will be 23. And sum of digits will be = 5

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