Question
If in a ΔABC, D is a point on BC such that BD = 5cm , BC = 8 cm then what is ratio of area of ΔABD to area of ΔADC ?
Solution
CD = BC - BD = 8 - 5 = 3 cm So Area of ΔABD / Area of ΔADC = BD/CD = 5/3
More Geometry Questions
- A and B are the centres of two circles with radii 11 cm and 6 cm respectively. A common tangent touches these circles at P & Q respectively. If AB =13 ...
- What is the angle traced by the hour hand in 18 minutes?
- In ∆ABC , G is the centroid , AB = 5 cm, BC= 8 cm and AC = 7 cm , find GD, where D is the mid-point of BC?
- The ratio of the angles ∠A and ∠B of a non-square rhombus ABCD is 7:5, then the value of the ∠C is
- If G is the centroid and AD, BE, CF are three medians of ∆ABC with area 60 cm² , then the area of ∆EFG is?
- In a given Figure, ON ∥ QR and MN ∥ OR. If, PO : OQ = 2 : 3 then find MO : OQ?
- ∆ABC and ∆DEF are similar and their areas are respectively 25 cm2 and 36 cm 2 . If EF = 7.2 cm BC is?
- Find the difference between angle and its complement if the angle is five-thirteenth of its complement.
- 10 identical solid spherical balls of radius 3 cm are melted to form a single sphere. In this process 20% of solid is wasted. What is the radius (in cm) of...
- If I is the incentre of ΔABC , if ∠ BIC = 1200 , then what is the measure of ∠ BAC?
