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    Question

    If in a ΔABC, the external angle bisector of angle A,

    meets BC when extended at a point D, BD = 9 cm , BC = 5 cm then what is AB:AC ?
    A 3:3 Correct Answer Incorrect Answer
    B 3:5 Correct Answer Incorrect Answer
    C 5:4 Correct Answer Incorrect Answer
    D 5:3 Correct Answer Incorrect Answer

    Solution

      Here CD = BD- BC = 9 - 5 = 4 cm, By External angle bisector theorem, AB: AC = BD:CD = 5:4

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