Question
If in a ΔABC, the external angle bisector of angle A, meets BC when extended at a point D, BD = 5cm , BC = 3 cm then what is AB:AC ?
Here CD = BD- BC = 5 - 3 = 2cm, By External angle bisector theorem, AB: AC = BD:CD = 3:2More Geometry Questions
- Find the area of triangle having sides 5 m, 6 m, and 9 m.
- Given are three points A(2, 7), B(4, -1), C(- 2, 6) on a plane. What kind of triangle is formed by joining the points A, B, and C?
- AB is the diameter of a circle with centre 'O'. PQ is a chord that cuts AB at 'C'. If radius of the circle is 7.5 cm and AC:CB = 3:2, the find the length o...
- The volume (in cu.cm.) of a right circular cylinder with radius 1 cm and height 2 cm on is: (Take π = 22/7)
- In the given figure, AB, AE, EF, FG and GB are semicircles. AB = 56 cm and AE = EF = FG = GB. What is the area (in cm2) of the shaded region?
- If in a ΔABC, AD is internal angle bisector & D is a point on BC, AB = 9 cm, BC = 12 cm then what is BD:CD?
- In ∆ABC, AB = 5cm, BC = 10cm, and AC = 13cm then find out the value of cos A.
- The radius of the incircle of a triangle is 8 cm. if the area of the triangle is 56 cm 2 , then its perimeter is?
- Question 9
- The measure of an angle is one-third of its supplementary angle. Find its measure.
Relevant for Exams:
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
